Base | Representation |
---|---|
bin | 1001011110000101001101… |
… | …1011011100101110110001 |
3 | 1100212102020002101201212102 |
4 | 2113201103123130232301 |
5 | 2331044044002230001 |
6 | 34051220221310145 |
7 | 2123161663224413 |
oct | 227412333345661 |
9 | 40772202351772 |
10 | 10412400430001 |
11 | 3354968656a79 |
12 | 1201baba05355 |
13 | 5a6b678905bb |
14 | 27dd6a1869b3 |
15 | 130cb5307e6b |
hex | 978536dcbb1 |
10412400430001 has 2 divisors, whose sum is σ = 10412400430002. Its totient is φ = 10412400430000.
The previous prime is 10412400429989. The next prime is 10412400430127. The reversal of 10412400430001 is 10003400421401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10132507585600 + 279892844401 = 3183160^2 + 529049^2 .
It is a cyclic number.
It is not a de Polignac number, because 10412400430001 - 230 = 10411326688177 is a prime.
It is not a weakly prime, because it can be changed into another prime (10412400730001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206200215000 + 5206200215001.
It is an arithmetic number, because the mean of its divisors is an integer number (5206200215001).
Almost surely, 210412400430001 is an apocalyptic number.
It is an amenable number.
10412400430001 is a deficient number, since it is larger than the sum of its proper divisors (1).
10412400430001 is an equidigital number, since it uses as much as digits as its factorization.
10412400430001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 10412400430001 its reverse (10003400421401), we get a palindrome (20415800851402).
The spelling of 10412400430001 in words is "ten trillion, four hundred twelve billion, four hundred million, four hundred thirty thousand, one".
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