1041300314113 has 2 divisors, whose sum is σ = 1041300314114. Its totient is φ = 1041300314112.

The previous prime is 1041300314099. The next prime is 1041300314147. The reversal of 1041300314113 is 3114130031401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 939827485809 + 101472828304 = 969447^2 + 318548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1041300314113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1041300312113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520650157056 + 520650157057.

It is an arithmetic number, because the mean of its divisors is an integer number (520650157057).

Almost surely, 2^{1041300314113} is an apocalyptic number.

It is an amenable number.

1041300314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041300314113 is an equidigital number, since it uses as much as digits as its factorization.

1041300314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1041300314113 its reverse (3114130031401), we get a palindrome (4155430345514).

The spelling of 1041300314113 in words is "one trillion, forty-one billion, three hundred million, three hundred fourteen thousand, one hundred thirteen".