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1041310316131 = 7523138416897
BaseRepresentation
bin11110010011100101110…
…11100111011001100011
310200112210201001220210121
433021302323213121203
5114030100420104011
62114212113541111
7135142432434331
oct17116273473143
93615721056717
101041310316131
11371687587928
12149990874797
137726c958797
1438584a5cb51
151c1482c9e71
hexf272ee7663

1041310316131 has 4 divisors (see below), whose sum is σ = 1041448740552. Its totient is φ = 1041171891712.

The previous prime is 1041310316113. The next prime is 1041310316143. The reversal of 1041310316131 is 1316130131401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1041310316131 - 219 = 1041309791843 is a prime.

It is a super-2 number, since 2×10413103161312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1041310316096 and 1041310316105.

It is not an unprimeable number, because it can be changed into a prime (1041310316161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69200926 + ... + 69215971.

It is an arithmetic number, because the mean of its divisors is an integer number (260362185138).

Almost surely, 21041310316131 is an apocalyptic number.

1041310316131 is a deficient number, since it is larger than the sum of its proper divisors (138424421).

1041310316131 is an equidigital number, since it uses as much as digits as its factorization.

1041310316131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138424420.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 1041310316131 its reverse (1316130131401), we get a palindrome (2357440447532).

The spelling of 1041310316131 in words is "one trillion, forty-one billion, three hundred ten million, three hundred sixteen thousand, one hundred thirty-one".

Divisors: 1 7523 138416897 1041310316131