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10413220524153 = 33471073508051
BaseRepresentation
bin1001011110001000010001…
…0011110111000001111001
31100212111100020112211112220
42113202010103313001321
52331102233423233103
634051433434554253
72123221212011436
oct227420423670171
940774306484486
1010413220524153
113355249571937
12120219a598989
135a6c6875a705
14280007062b8d
15130d122edc53
hex978844f7079

10413220524153 has 4 divisors (see below), whose sum is σ = 13884294032208. Its totient is φ = 6942147016100.

The previous prime is 10413220524131. The next prime is 10413220524167. The reversal of 10413220524153 is 35142502231401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10413220524153 - 25 = 10413220524121 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10413220524653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1735536754023 + ... + 1735536754028.

It is an arithmetic number, because the mean of its divisors is an integer number (3471073508052).

Almost surely, 210413220524153 is an apocalyptic number.

It is an amenable number.

10413220524153 is a deficient number, since it is larger than the sum of its proper divisors (3471073508055).

10413220524153 is an equidigital number, since it uses as much as digits as its factorization.

10413220524153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3471073508054.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 10413220524153 its reverse (35142502231401), we get a palindrome (45555722755554).

The spelling of 10413220524153 in words is "ten trillion, four hundred thirteen billion, two hundred twenty million, five hundred twenty-four thousand, one hundred fifty-three".

Divisors: 1 3 3471073508051 10413220524153