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10413433 is a prime number
BaseRepresentation
bin100111101110…
…010101111001
3201121001112201
4213232111321
510131212213
61011110201
7154340602
oct47562571
921531481
1010413433
115972848
1235a2361
132207ac4
141550da9
15daa6dd
hex9ee579

10413433 has 2 divisors, whose sum is σ = 10413434. Its totient is φ = 10413432.

The previous prime is 10413421. The next prime is 10413449. The reversal of 10413433 is 33431401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8020224 + 2393209 = 2832^2 + 1547^2 .

It is a cyclic number.

It is not a de Polignac number, because 10413433 - 217 = 10282361 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10413433.

It is not a weakly prime, because it can be changed into another prime (10413833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206716 + 5206717.

It is an arithmetic number, because the mean of its divisors is an integer number (5206717).

Almost surely, 210413433 is an apocalyptic number.

It is an amenable number.

10413433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413433 is an equidigital number, since it uses as much as digits as its factorization.

10413433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 10413433 is about 3226.9851254693. The cubic root of 10413433 is about 218.3725149010.

Adding to 10413433 its reverse (33431401), we get a palindrome (43844834).

It can be divided in two parts, 1041 and 3433, that multiplied together give a palindrome (3573753).

The spelling of 10413433 in words is "ten million, four hundred thirteen thousand, four hundred thirty-three".