Base | Representation |
---|---|
bin | 11110010011101010110… |
… | …00011001010100001011 |
3 | 10200112220120101221220211 |
4 | 33021311120121110023 |
5 | 114030141430240201 |
6 | 2114220142501551 |
7 | 135143441660263 |
oct | 17116530312413 |
9 | 3615816357824 |
10 | 1041351415051 |
11 | 3716a87a9082 |
12 | 1499a25948b7 |
13 | 7727831857c |
14 | 3858a2ba7a3 |
15 | 1c14bbe7651 |
hex | f27561950b |
1041351415051 has 2 divisors, whose sum is σ = 1041351415052. Its totient is φ = 1041351415050.
The previous prime is 1041351415031. The next prime is 1041351415099. The reversal of 1041351415051 is 1505141531401.
1041351415051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1505141531401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1041351415051 - 25 = 1041351415019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1041351415031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520675707525 + 520675707526.
It is an arithmetic number, because the mean of its divisors is an integer number (520675707526).
Almost surely, 21041351415051 is an apocalyptic number.
1041351415051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041351415051 is an equidigital number, since it uses as much as digits as its factorization.
1041351415051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 1041351415051 its reverse (1505141531401), we get a palindrome (2546492946452).
The spelling of 1041351415051 in words is "one trillion, forty-one billion, three hundred fifty-one million, four hundred fifteen thousand, fifty-one".
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