Base | Representation |
---|---|
bin | 10111101011011100000011… |
… | …100101010000001001010001 |
3 | 111122201200212212022122221112 |
4 | 113223130003211100021101 |
5 | 102122212442310420332 |
6 | 1005253152150303105 |
7 | 30635606361430511 |
oct | 2753340345201121 |
9 | 448650785278845 |
10 | 104140132123217 |
11 | 30200644724023 |
12 | b81b07b657a95 |
13 | 46154abcb3688 |
14 | 1ba05a3133841 |
15 | c08dccd98db2 |
hex | 5eb703950251 |
104140132123217 has 2 divisors, whose sum is σ = 104140132123218. Its totient is φ = 104140132123216.
The previous prime is 104140132123117. The next prime is 104140132123267. The reversal of 104140132123217 is 712321231041401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101358361800721 + 2781770322496 = 10067689^2 + 1667864^2 .
It is a cyclic number.
It is not a de Polignac number, because 104140132123217 - 222 = 104140127928913 is a prime.
It is not a weakly prime, because it can be changed into another prime (104140132123267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52070066061608 + 52070066061609.
It is an arithmetic number, because the mean of its divisors is an integer number (52070066061609).
Almost surely, 2104140132123217 is an apocalyptic number.
It is an amenable number.
104140132123217 is a deficient number, since it is larger than the sum of its proper divisors (1).
104140132123217 is an equidigital number, since it uses as much as digits as its factorization.
104140132123217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 104140132123217 its reverse (712321231041401), we get a palindrome (816461363164618).
The spelling of 104140132123217 in words is "one hundred four trillion, one hundred forty billion, one hundred thirty-two million, one hundred twenty-three thousand, two hundred seventeen".
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