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104143121134147 is a prime number
BaseRepresentation
bin10111101011011110110101…
…101111011011001001000011
3111122201222121011200011010001
4113223132311233123021003
5102122240103002243042
61005254404523220431
730636043424544214
oct2753366557331103
9448658534604101
10104143121134147
1130201938969197
12b81b774677717
13461586731b0b4
141ba07a80b940b
15c090054bbbb7
hex5eb7b5bdb243

104143121134147 has 2 divisors, whose sum is σ = 104143121134148. Its totient is φ = 104143121134146.

The previous prime is 104143121134109. The next prime is 104143121134159. The reversal of 104143121134147 is 741431121341401.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-104143121134147 is a prime.

It is not a weakly prime, because it can be changed into another prime (104143121134177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52071560567073 + 52071560567074.

It is an arithmetic number, because the mean of its divisors is an integer number (52071560567074).

Almost surely, 2104143121134147 is an apocalyptic number.

104143121134147 is a deficient number, since it is larger than the sum of its proper divisors (1).

104143121134147 is an equidigital number, since it uses as much as digits as its factorization.

104143121134147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 37.

Adding to 104143121134147 its reverse (741431121341401), we get a palindrome (845574242475548).

The spelling of 104143121134147 in words is "one hundred four trillion, one hundred forty-three billion, one hundred twenty-one million, one hundred thirty-four thousand, one hundred forty-seven".