Base | Representation |
---|---|
bin | 11110010100110111010… |
… | …00000000100000100001 |
3 | 10200121120021201222120011 |
4 | 33022123220000200201 |
5 | 114033000204320303 |
6 | 2114403543044521 |
7 | 135165362501533 |
oct | 17123350004041 |
9 | 3617507658504 |
10 | 1041993041953 |
11 | 3719a79a8946 |
12 | 149b41440741 |
13 | 7734b22a366 |
14 | 3860b5bb853 |
15 | 1c1881d916d |
hex | f29ba00821 |
1041993041953 has 2 divisors, whose sum is σ = 1041993041954. Its totient is φ = 1041993041952.
The previous prime is 1041993041849. The next prime is 1041993041983. The reversal of 1041993041953 is 3591403991401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 537300728064 + 504692313889 = 733008^2 + 710417^2 .
It is an emirp because it is prime and its reverse (3591403991401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1041993041953 - 221 = 1041990944801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1041993041897 and 1041993041906.
It is not a weakly prime, because it can be changed into another prime (1041993041983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520996520976 + 520996520977.
It is an arithmetic number, because the mean of its divisors is an integer number (520996520977).
Almost surely, 21041993041953 is an apocalyptic number.
It is an amenable number.
1041993041953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041993041953 is an equidigital number, since it uses as much as digits as its factorization.
1041993041953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 524880, while the sum is 49.
The spelling of 1041993041953 in words is "one trillion, forty-one billion, nine hundred ninety-three million, forty-one thousand, nine hundred fifty-three".
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