Base | Representation |
---|---|
bin | 11110010101011110001… |
… | …11011011000000110001 |
3 | 10200122102002001102011002 |
4 | 33022233013123000301 |
5 | 114034132412402311 |
6 | 2114500223531345 |
7 | 135206443122521 |
oct | 17125707330061 |
9 | 3618362042132 |
10 | 1042320044081 |
11 | 372055545438 |
12 | 14a012a59b55 |
13 | 773a0bc0744 |
14 | 3863cbbd681 |
15 | 1c1a6c7d93b |
hex | f2af1db031 |
1042320044081 has 2 divisors, whose sum is σ = 1042320044082. Its totient is φ = 1042320044080.
The previous prime is 1042320044047. The next prime is 1042320044149. The reversal of 1042320044081 is 1804400232401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1032680731681 + 9639312400 = 1016209^2 + 98180^2 .
It is a cyclic number.
It is not a de Polignac number, because 1042320044081 - 210 = 1042320043057 is a prime.
It is a super-2 number, since 2×10423200440812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1042320044581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521160022040 + 521160022041.
It is an arithmetic number, because the mean of its divisors is an integer number (521160022041).
Almost surely, 21042320044081 is an apocalyptic number.
It is an amenable number.
1042320044081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1042320044081 is an equidigital number, since it uses as much as digits as its factorization.
1042320044081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 1042320044081 its reverse (1804400232401), we get a palindrome (2846720276482).
The spelling of 1042320044081 in words is "one trillion, forty-two billion, three hundred twenty million, forty-four thousand, eighty-one".
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