Base | Representation |
---|---|
bin | 1001011110101110010011… |
… | …1010010100110110101001 |
3 | 1100220110200211122122000221 |
4 | 2113223210322110312221 |
5 | 2331234141333430423 |
6 | 34100242544130041 |
7 | 2124032224646014 |
oct | 227534472246651 |
9 | 40813624578027 |
10 | 10423431155113 |
11 | 3359609170019 |
12 | 120416a006921 |
13 | 5a7c04c84c92 |
14 | 2806d517437b |
15 | 13120d915e5d |
hex | 97ae4e94da9 |
10423431155113 has 2 divisors, whose sum is σ = 10423431155114. Its totient is φ = 10423431155112.
The previous prime is 10423431155101. The next prime is 10423431155171. The reversal of 10423431155113 is 31155113432401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8783707367824 + 1639723787289 = 2963732^2 + 1280517^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10423431155113 is a prime.
It is not a weakly prime, because it can be changed into another prime (10423431155213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211715577556 + 5211715577557.
It is an arithmetic number, because the mean of its divisors is an integer number (5211715577557).
Almost surely, 210423431155113 is an apocalyptic number.
It is an amenable number.
10423431155113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10423431155113 is an equidigital number, since it uses as much as digits as its factorization.
10423431155113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 10423431155113 its reverse (31155113432401), we get a palindrome (41578544587514).
The spelling of 10423431155113 in words is "ten trillion, four hundred twenty-three billion, four hundred thirty-one million, one hundred fifty-five thousand, one hundred thirteen".
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