Base | Representation |
---|---|
bin | 10011011010101001… |
… | …10111011100101011 |
3 | 222220110211012221102 |
4 | 21231110313130223 |
5 | 132322033334011 |
6 | 4442213032015 |
7 | 516214365464 |
oct | 115524673453 |
9 | 28813735842 |
10 | 10424121131 |
11 | 446a165546 |
12 | 202b02560b |
13 | ca1825c18 |
14 | 70c605d6b |
15 | 41023873b |
hex | 26d53772b |
10424121131 has 2 divisors, whose sum is σ = 10424121132. Its totient is φ = 10424121130.
The previous prime is 10424121119. The next prime is 10424121161. The reversal of 10424121131 is 13112142401.
It is a weak prime.
It is an emirp because it is prime and its reverse (13112142401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10424121131 - 210 = 10424120107 is a prime.
It is a super-2 number, since 2×104241211312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10424121161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5212060565 + 5212060566.
It is an arithmetic number, because the mean of its divisors is an integer number (5212060566).
Almost surely, 210424121131 is an apocalyptic number.
10424121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10424121131 is an equidigital number, since it uses as much as digits as its factorization.
10424121131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 10424121131 its reverse (13112142401), we get a palindrome (23536263532).
The spelling of 10424121131 in words is "ten billion, four hundred twenty-four million, one hundred twenty-one thousand, one hundred thirty-one".
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