Base | Representation |
---|---|
bin | 10111101100111100000100… |
… | …110000110000011001010001 |
3 | 111200002120000000021220222022 |
4 | 113230330010300300121101 |
5 | 102130410114132144332 |
6 | 1005412402420021225 |
7 | 30646216305512663 |
oct | 2754740460603121 |
9 | 450076000256868 |
10 | 104243231131217 |
11 | 302403403a3762 |
12 | b837053231815 |
13 | 462212c861759 |
14 | 1ba55839b0533 |
15 | c0b9141d3212 |
hex | 5ecf04c30651 |
104243231131217 has 2 divisors, whose sum is σ = 104243231131218. Its totient is φ = 104243231131216.
The previous prime is 104243231131201. The next prime is 104243231131261. The reversal of 104243231131217 is 712131132342401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73644013028881 + 30599218102336 = 8581609^2 + 5531656^2 .
It is a cyclic number.
It is not a de Polignac number, because 104243231131217 - 24 = 104243231131201 is a prime.
It is not a weakly prime, because it can be changed into another prime (104243231131517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52121615565608 + 52121615565609.
It is an arithmetic number, because the mean of its divisors is an integer number (52121615565609).
Almost surely, 2104243231131217 is an apocalyptic number.
It is an amenable number.
104243231131217 is a deficient number, since it is larger than the sum of its proper divisors (1).
104243231131217 is an equidigital number, since it uses as much as digits as its factorization.
104243231131217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 104243231131217 its reverse (712131132342401), we get a palindrome (816374363473618).
The spelling of 104243231131217 in words is "one hundred four trillion, two hundred forty-three billion, two hundred thirty-one million, one hundred thirty-one thousand, two hundred seventeen".
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