Base | Representation |
---|---|
bin | 11110010101111010001… |
… | …01000010011110011001 |
3 | 10200200000101211212021211 |
4 | 33022331011002132121 |
5 | 114040122400102223 |
6 | 2114535352503121 |
7 | 135215316223351 |
oct | 17127505023631 |
9 | 3620011755254 |
10 | 1042554300313 |
11 | 3721657a5629 |
12 | 14a0793aaaa1 |
13 | 7740a5b00b6 |
14 | 38661d5bb61 |
15 | 1c1bc602d0d |
hex | f2bd142799 |
1042554300313 has 2 divisors, whose sum is σ = 1042554300314. Its totient is φ = 1042554300312.
The previous prime is 1042554300289. The next prime is 1042554300371. The reversal of 1042554300313 is 3130034552401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1042549228809 + 5071504 = 1021053^2 + 2252^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1042554300313 is a prime.
It is a super-2 number, since 2×10425543003132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1042554300413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521277150156 + 521277150157.
It is an arithmetic number, because the mean of its divisors is an integer number (521277150157).
Almost surely, 21042554300313 is an apocalyptic number.
It is an amenable number.
1042554300313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1042554300313 is an equidigital number, since it uses as much as digits as its factorization.
1042554300313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1042554300313 its reverse (3130034552401), we get a palindrome (4172588852714).
The spelling of 1042554300313 in words is "one trillion, forty-two billion, five hundred fifty-four million, three hundred thousand, three hundred thirteen".
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