1043112121 has 4 divisors (see below), whose sum is σ = 1045590244. Its totient is φ = 1040634000.

The previous prime is 1043112113. The next prime is 1043112131. The reversal of 1043112121 is 1212113401.

1043112121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1212113401 = 8053 ⋅150517.

It can be written as a sum of positive squares in 2 ways, for example, as 547560000 + 495552121 = 23400^2 + 22261^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043112121 - 2³ = 1043112113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1043112095 and 1043112104.

It is not an unprimeable number, because it can be changed into a prime (1043112131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1238430 + ... + 1239271.

It is an arithmetic number, because the mean of its divisors is an integer number (261397561).

Almost surely, 2^1043112121 is an apocalyptic number.

It is an amenable number.

1043112121 is a deficient number, since it is larger than the sum of its proper divisors (2478123).

1043112121 is an equidigital number, since it uses as much as digits as its factorization.

1043112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2478122.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1043112121 is about 32297.2463377298. The cubic root of 1043112121 is about 1014.1689982955.

Adding to 1043112121 its reverse (1212113401), we get a palindrome (2255225522).

The spelling of 1043112121 in words is "one billion, forty-three million, one hundred twelve thousand, one hundred twenty-one".