1043124443131 has 4 divisors (see below), whose sum is σ = 1043229490264. Its totient is φ = 1043019396000.

The previous prime is 1043124443117. The next prime is 1043124443147. The reversal of 1043124443131 is 1313444213401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1043124443131 - 2¹⁷ = 1043124312059 is a prime.

It is a super-2 number, since 2×1043124443131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1043124443093 and 1043124443102.

It is not an unprimeable number, because it can be changed into a prime (1043124446131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52508670 + ... + 52528531.

It is an arithmetic number, because the mean of its divisors is an integer number (260807372566).

Almost surely, 2^{1043124443131} is an apocalyptic number.

1043124443131 is a deficient number, since it is larger than the sum of its proper divisors (105047133).

1043124443131 is an equidigital number, since it uses as much as digits as its factorization.

1043124443131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105047132.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1043124443131 its reverse (1313444213401), we get a palindrome (2356568656532).

The spelling of 1043124443131 in words is "one trillion, forty-three billion, one hundred twenty-four million, four hundred forty-three thousand, one hundred thirty-one".