Base | Representation |
---|---|
bin | 1001011111001100001001… |
… | …0110110001011001010011 |
3 | 1100221020101002020101120111 |
4 | 2113303002112301121103 |
5 | 2331402042441002313 |
6 | 34104045450222151 |
7 | 2124434561303434 |
oct | 227630226613123 |
9 | 40836332211514 |
10 | 10431441344083 |
11 | 3361a49767601 |
12 | 1205824724957 |
13 | 5a88b0654976 |
14 | 280c54d3148b |
15 | 13152bc7543d |
hex | 97cc25b1653 |
10431441344083 has 2 divisors, whose sum is σ = 10431441344084. Its totient is φ = 10431441344082.
The previous prime is 10431441343993. The next prime is 10431441344131. The reversal of 10431441344083 is 38044314413401.
10431441344083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10431441344083 - 221 = 10431439246931 is a prime.
It is a super-2 number, since 2×104314413440832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10431441342083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5215720672041 + 5215720672042.
It is an arithmetic number, because the mean of its divisors is an integer number (5215720672042).
Almost surely, 210431441344083 is an apocalyptic number.
10431441344083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10431441344083 is an equidigital number, since it uses as much as digits as its factorization.
10431441344083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 221184, while the sum is 40.
Adding to 10431441344083 its reverse (38044314413401), we get a palindrome (48475755757484).
The spelling of 10431441344083 in words is "ten trillion, four hundred thirty-one billion, four hundred forty-one million, three hundred forty-four thousand, eighty-three".
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