Base | Representation |
---|---|
bin | 1001011111001110010110… |
… | …0000001011101000011011 |
3 | 1100221021220011210200210221 |
4 | 2113303211200023220123 |
5 | 2331404244414412103 |
6 | 34104224153020511 |
7 | 2124455311355116 |
oct | 227634540135033 |
9 | 40837804720727 |
10 | 10432031013403 |
11 | 33622215a991a |
12 | 120596a0b4737 |
13 | 5a897587431c |
14 | 280cad38957d |
15 | 1315639021bd |
hex | 97ce580ba1b |
10432031013403 has 2 divisors, whose sum is σ = 10432031013404. Its totient is φ = 10432031013402.
The previous prime is 10432031013373. The next prime is 10432031013413. The reversal of 10432031013403 is 30431013023401.
10432031013403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10432031013403 - 213 = 10432031005211 is a prime.
It is not a weakly prime, because it can be changed into another prime (10432031013413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5216015506701 + 5216015506702.
It is an arithmetic number, because the mean of its divisors is an integer number (5216015506702).
Almost surely, 210432031013403 is an apocalyptic number.
10432031013403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10432031013403 is an equidigital number, since it uses as much as digits as its factorization.
10432031013403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10432031013403 its reverse (30431013023401), we get a palindrome (40863044036804).
The spelling of 10432031013403 in words is "ten trillion, four hundred thirty-two billion, thirty-one million, thirteen thousand, four hundred three".
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