10433132124131 has 4 divisors (see below), whose sum is σ = 10433183785752. Its totient is φ = 10433080462512.

The previous prime is 10433132124109. The next prime is 10433132124139. The reversal of 10433132124131 is 13142123133401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10433132124131 - 2⁶ = 10433132124067 is a prime.

It is a super-2 number, since 2×10433132124131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10433132124094 and 10433132124103.

It is not an unprimeable number, because it can be changed into a prime (10433132124139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25526690 + ... + 25932183.

It is an arithmetic number, because the mean of its divisors is an integer number (2608295946438).

Almost surely, 2^{10433132124131} is an apocalyptic number.

10433132124131 is a deficient number, since it is larger than the sum of its proper divisors (51661621).

10433132124131 is an equidigital number, since it uses as much as digits as its factorization.

10433132124131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51661620.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 10433132124131 its reverse (13142123133401), we get a palindrome (23575255257532).

The spelling of 10433132124131 in words is "ten trillion, four hundred thirty-three billion, one hundred thirty-two million, one hundred twenty-four thousand, one hundred thirty-one".