10433140130131 has 4 divisors (see below), whose sum is σ = 10675771295992. Its totient is φ = 10190508964272.

The previous prime is 10433140130041. The next prime is 10433140130167. The reversal of 10433140130131 is 13103104133401.

10433140130131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10433140130131 - 2¹¹ = 10433140128083 is a prime.

It is a super-2 number, since 2×10433140130131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10433140130096 and 10433140130105.

It is not an unprimeable number, because it can be changed into a prime (10433140131131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121315582866 + ... + 121315582951.

It is an arithmetic number, because the mean of its divisors is an integer number (2668942823998).

Almost surely, 2^{10433140130131} is an apocalyptic number.

10433140130131 is a deficient number, since it is larger than the sum of its proper divisors (242631165861).

10433140130131 is an equidigital number, since it uses as much as digits as its factorization.

10433140130131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242631165860.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 10433140130131 its reverse (13103104133401), we get a palindrome (23536244263532).

The spelling of 10433140130131 in words is "ten trillion, four hundred thirty-three billion, one hundred forty million, one hundred thirty thousand, one hundred thirty-one".