1043314081 has 2 divisors, whose sum is σ = 1043314082. Its totient is φ = 1043314080.

The previous prime is 1043314039. The next prime is 1043314087. The reversal of 1043314081 is 1804133401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 527115681 + 516198400 = 22959^2 + 22720^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043314081 - 2²⁵ = 1009759649 is a prime.

It is a super-2 number, since 2×1043314081² = 2177008543225749122, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1043314087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521657040 + 521657041.

It is an arithmetic number, because the mean of its divisors is an integer number (521657041).

Almost surely, 2^1043314081 is an apocalyptic number.

It is an amenable number.

1043314081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043314081 is an equidigital number, since it uses as much as digits as its factorization.

1043314081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

The square root of 1043314081 is about 32300.3727687468. The cubic root of 1043314081 is about 1014.2344461509.

Adding to 1043314081 its reverse (1804133401), we get a palindrome (2847447482).

The spelling of 1043314081 in words is "one billion, forty-three million, three hundred fourteen thousand, eighty-one".