Base | Representation |
---|---|
bin | 10111101110010110100000… |
… | …010111110010101000101001 |
3 | 111200102211122002001002002221 |
4 | 113232112200113302220221 |
5 | 102134002444231104001 |
6 | 1005525141505354041 |
7 | 30656224446653614 |
oct | 2756264027625051 |
9 | 450384562032087 |
10 | 104340331113001 |
11 | 30278538848195 |
12 | b851a31938921 |
13 | 462b3355c5089 |
14 | 1baa15581317b |
15 | c0e1e8a281a1 |
hex | 5ee5a05f2a29 |
104340331113001 has 2 divisors, whose sum is σ = 104340331113002. Its totient is φ = 104340331113000.
The previous prime is 104340331112993. The next prime is 104340331113019. The reversal of 104340331113001 is 100311133043401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95388721891225 + 8951609221776 = 9766715^2 + 2991924^2 .
It is a cyclic number.
It is not a de Polignac number, because 104340331113001 - 23 = 104340331112993 is a prime.
It is not a weakly prime, because it can be changed into another prime (104340331113091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52170165556500 + 52170165556501.
It is an arithmetic number, because the mean of its divisors is an integer number (52170165556501).
Almost surely, 2104340331113001 is an apocalyptic number.
It is an amenable number.
104340331113001 is a deficient number, since it is larger than the sum of its proper divisors (1).
104340331113001 is an equidigital number, since it uses as much as digits as its factorization.
104340331113001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 104340331113001 its reverse (100311133043401), we get a palindrome (204651464156402).
The spelling of 104340331113001 in words is "one hundred four trillion, three hundred forty billion, three hundred thirty-one million, one hundred thirteen thousand, one".
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