10442423000131 has 2 divisors, whose sum is σ = 10442423000132. Its totient is φ = 10442423000130.

The previous prime is 10442423000027. The next prime is 10442423000137. The reversal of 10442423000131 is 13100032424401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10442423000131 - 2¹⁷ = 10442422869059 is a prime.

It is a super-2 number, since 2×10442423000131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10442423000096 and 10442423000105.

It is not a weakly prime, because it can be changed into another prime (10442423000137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5221211500065 + 5221211500066.

It is an arithmetic number, because the mean of its divisors is an integer number (5221211500066).

Almost surely, 2^{10442423000131} is an apocalyptic number.

10442423000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10442423000131 is an equidigital number, since it uses as much as digits as its factorization.

10442423000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 10442423000131 its reverse (13100032424401), we get a palindrome (23542455424532).

The spelling of 10442423000131 in words is "ten trillion, four hundred forty-two billion, four hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.