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104512601565193 is a prime number
BaseRepresentation
bin10111110000110110111100…
…011111011010100000001001
3111201001022021220021210010011
4113300312330133122200021
5102144313302000041233
61010140232031151521
731004533460440123
oct2760667437324011
9451038256253104
10104512601565193
11303345aaa44728
12b87b2aa9755a1
13464165aa4a0a3
141bb4618c26213
15c1392c85a0cd
hex5f0dbc7da809

104512601565193 has 2 divisors, whose sum is σ = 104512601565194. Its totient is φ = 104512601565192.

The previous prime is 104512601565137. The next prime is 104512601565223. The reversal of 104512601565193 is 391565106215401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79601602212729 + 24910999352464 = 8921973^2 + 4991092^2 .

It is a cyclic number.

It is not a de Polignac number, because 104512601565193 - 241 = 102313578309641 is a prime.

It is not a weakly prime, because it can be changed into another prime (104512601565293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52256300782596 + 52256300782597.

It is an arithmetic number, because the mean of its divisors is an integer number (52256300782597).

Almost surely, 2104512601565193 is an apocalyptic number.

It is an amenable number.

104512601565193 is a deficient number, since it is larger than the sum of its proper divisors (1).

104512601565193 is an equidigital number, since it uses as much as digits as its factorization.

104512601565193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 49.

The spelling of 104512601565193 in words is "one hundred four trillion, five hundred twelve billion, six hundred one million, five hundred sixty-five thousand, one hundred ninety-three".