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10455312113 = 89191361409
BaseRepresentation
bin10011011110010111…
…10110011011110001
3222222122111212220222
421233023312123301
5132403024441423
64445245342425
7520043454341
oct115713663361
928878455828
1010455312113
114485829814
122039567a15
13ca812701c
14712804d21
15412d4a3c8
hex26f2f66f1

10455312113 has 8 divisors (see below), whose sum is σ = 10578486600. Its totient is φ = 10332264448.

The previous prime is 10455312083. The next prime is 10455312149. The reversal of 10455312113 is 31121355401.

It can be written as a sum of positive squares in 4 ways, for example, as 4831362064 + 5623950049 = 69508^2 + 74993^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10455312113 - 28 = 10455311857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10455315113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139553 + ... + 200961.

It is an arithmetic number, because the mean of its divisors is an integer number (1322310825).

Almost surely, 210455312113 is an apocalyptic number.

It is an amenable number.

10455312113 is a deficient number, since it is larger than the sum of its proper divisors (123174487).

10455312113 is an equidigital number, since it uses as much as digits as its factorization.

10455312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63411.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 10455312113 its reverse (31121355401), we get a palindrome (41576667514).

The spelling of 10455312113 in words is "ten billion, four hundred fifty-five million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 89 1913 61409 170257 5465401 117475417 10455312113