Base | Representation |
---|---|
bin | 11110011100100100111… |
… | …01010100110111110011 |
3 | 10201000020220002022211111 |
4 | 33032102131110313303 |
5 | 114114440324323011 |
6 | 2120330514454151 |
7 | 135403116050026 |
oct | 17162235246763 |
9 | 3630226068744 |
10 | 1046134214131 |
11 | 373732544896 |
12 | 14a8b8294357 |
13 | 7785b1797b6 |
14 | 388c159d1bd |
15 | 1c32ba48121 |
hex | f392754df3 |
1046134214131 has 2 divisors, whose sum is σ = 1046134214132. Its totient is φ = 1046134214130.
The previous prime is 1046134213973. The next prime is 1046134214137. The reversal of 1046134214131 is 1314124316401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1046134214131 - 213 = 1046134205939 is a prime.
It is a super-2 number, since 2×10461342141312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1046134214093 and 1046134214102.
It is not a weakly prime, because it can be changed into another prime (1046134214137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 523067107065 + 523067107066.
It is an arithmetic number, because the mean of its divisors is an integer number (523067107066).
Almost surely, 21046134214131 is an apocalyptic number.
1046134214131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1046134214131 is an equidigital number, since it uses as much as digits as its factorization.
1046134214131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 1046134214131 in words is "one trillion, forty-six billion, one hundred thirty-four million, two hundred fourteen thousand, one hundred thirty-one".
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