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1046300041147 is a prime number
BaseRepresentation
bin11110011100111000101…
…01111001111110111011
310201000200110010012201211
433032130111321332323
5114120310302304042
62120355201023551
7135410201415514
oct17163425717673
93630613105654
101046300041147
11373808107109
1214a943924bb7
137788662a5aa
14388d9607a0b
151c33b3a2017
hexf39c579fbb

1046300041147 has 2 divisors, whose sum is σ = 1046300041148. Its totient is φ = 1046300041146.

The previous prime is 1046300041117. The next prime is 1046300041277. The reversal of 1046300041147 is 7411400036401.

It is a weak prime.

It is an emirp because it is prime and its reverse (7411400036401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1046300041147 - 219 = 1046299516859 is a prime.

It is a super-2 number, since 2×10463000411472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1046300041117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 523150020573 + 523150020574.

It is an arithmetic number, because the mean of its divisors is an integer number (523150020574).

Almost surely, 21046300041147 is an apocalyptic number.

1046300041147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1046300041147 is an equidigital number, since it uses as much as digits as its factorization.

1046300041147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 1046300041147 its reverse (7411400036401), we get a palindrome (8457700077548).

The spelling of 1046300041147 in words is "one trillion, forty-six billion, three hundred million, forty-one thousand, one hundred forty-seven".