104712416131 has 2 divisors, whose sum is σ = 104712416132. Its totient is φ = 104712416130.

The previous prime is 104712416071. The next prime is 104712416177. The reversal of 104712416131 is 131614217401.

It is a strong prime.

It is an emirp because it is prime and its reverse (131614217401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104712416131 - 2¹³ = 104712407939 is a prime.

It is a super-2 number, since 2×104712416131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 104712416093 and 104712416102.

It is not a weakly prime, because it can be changed into another prime (104712416231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52356208065 + 52356208066.

It is an arithmetic number, because the mean of its divisors is an integer number (52356208066).

Almost surely, 2^104712416131 is an apocalyptic number.

104712416131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104712416131 is an equidigital number, since it uses as much as digits as its factorization.

104712416131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 31.

The spelling of 104712416131 in words is "one hundred four billion, seven hundred twelve million, four hundred sixteen thousand, one hundred thirty-one".