Base | Representation |
---|---|
bin | 10111110100110101110100… |
… | …101110010010110110011011 |
3 | 111202000110200200220201210101 |
4 | 113310311310232102312123 |
5 | 102213304243001212103 |
6 | 1010510052251400231 |
7 | 31033362405660403 |
oct | 2764656456226633 |
9 | 452013620821711 |
10 | 104786275413403 |
11 | 3042a678775491 |
12 | b904347753077 |
13 | 46613c367bc8c |
14 | 1bc397b813803 |
15 | c1aae8bdca1d |
hex | 5f4d74b92d9b |
104786275413403 has 2 divisors, whose sum is σ = 104786275413404. Its totient is φ = 104786275413402.
The previous prime is 104786275413397. The next prime is 104786275413473. The reversal of 104786275413403 is 304314572687401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104786275413403 - 25 = 104786275413371 is a prime.
It is not a weakly prime, because it can be changed into another prime (104786275413473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52393137706701 + 52393137706702.
It is an arithmetic number, because the mean of its divisors is an integer number (52393137706702).
Almost surely, 2104786275413403 is an apocalyptic number.
104786275413403 is a deficient number, since it is larger than the sum of its proper divisors (1).
104786275413403 is an equidigital number, since it uses as much as digits as its factorization.
104786275413403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13547520, while the sum is 55.
The spelling of 104786275413403 in words is "one hundred four trillion, seven hundred eighty-six billion, two hundred seventy-five million, four hundred thirteen thousand, four hundred three".
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