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104861921291753 is a prime number
BaseRepresentation
bin10111110101111100010001…
…100100011010110111101001
3111202021200221120222111202112
4113311330101210122313221
5102221024203322314003
61011004522425212105
731042011110223653
oct2765742144326751
9452250846874675
10104861921291753
113045976690851a
12b916b39331035
13466858a6c5142
141bc74b61b76d3
15c1ca74cd63d8
hex5f5f1191ade9

104861921291753 has 2 divisors, whose sum is σ = 104861921291754. Its totient is φ = 104861921291752.

The previous prime is 104861921291749. The next prime is 104861921291819. The reversal of 104861921291753 is 357192129168401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65454701606464 + 39407219685289 = 8090408^2 + 6277517^2 .

It is a cyclic number.

It is not a de Polignac number, because 104861921291753 - 22 = 104861921291749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 104861921291692 and 104861921291701.

It is not a weakly prime, because it can be changed into another prime (104861921291353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52430960645876 + 52430960645877.

It is an arithmetic number, because the mean of its divisors is an integer number (52430960645877).

It is a 1-persistent number, because it is pandigital, but 2⋅104861921291753 = 209723842583506 is not.

Almost surely, 2104861921291753 is an apocalyptic number.

It is an amenable number.

104861921291753 is a deficient number, since it is larger than the sum of its proper divisors (1).

104861921291753 is an equidigital number, since it uses as much as digits as its factorization.

104861921291753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 59.

The spelling of 104861921291753 in words is "one hundred four trillion, eight hundred sixty-one billion, nine hundred twenty-one million, two hundred ninety-one thousand, seven hundred fifty-three".