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10491307 is a prime number
BaseRepresentation
bin101000000001…
…010110101011
3201202000100221
4220001112223
510141210212
61012510511
7155113621
oct50012653
921660327
1010491307
115a16302
12361b437
132234398
141571511
15dc3807
hexa015ab

10491307 has 2 divisors, whose sum is σ = 10491308. Its totient is φ = 10491306.

The previous prime is 10491281. The next prime is 10491317. The reversal of 10491307 is 70319401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10491307 - 27 = 10491179 is a prime.

It is a super-2 number, since 2×104913072 = 220135045136498, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10491317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5245653 + 5245654.

It is an arithmetic number, because the mean of its divisors is an integer number (5245654).

Almost surely, 210491307 is an apocalyptic number.

10491307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10491307 is an equidigital number, since it uses as much as digits as its factorization.

10491307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

The square root of 10491307 is about 3239.0287124383. The cubic root of 10491307 is about 218.9155098973.

The spelling of 10491307 in words is "ten million, four hundred ninety-one thousand, three hundred seven".