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105010100051 = 469332237447
BaseRepresentation
bin110000111001100010…
…1101111011101010011
3101001001100000210110212
41201303011233131103
53210030041200201
6120124014514335
710405151060123
oct1416305573523
9331040023425
10105010100051
114059751145a
12184278059ab
139b9679659c
1451225d0c83
152ae8ed8abb
hex187316f753

105010100051 has 4 divisors (see below), whose sum is σ = 105012384432. Its totient is φ = 105007815672.

The previous prime is 105010100023. The next prime is 105010100071. The reversal of 105010100051 is 150001010501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 105010100051 - 226 = 104942991187 is a prime.

It is a super-2 number, since 2×1050101000512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 105010099999 and 105010100035.

It is not an unprimeable number, because it can be changed into a prime (105010100071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1071791 + ... + 1165656.

It is an arithmetic number, because the mean of its divisors is an integer number (26253096108).

Almost surely, 2105010100051 is an apocalyptic number.

105010100051 is a deficient number, since it is larger than the sum of its proper divisors (2284381).

105010100051 is an equidigital number, since it uses as much as digits as its factorization.

105010100051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2284380.

The product of its (nonzero) digits is 25, while the sum is 14.

Adding to 105010100051 its reverse (150001010501), we get a palindrome (255011110552).

The spelling of 105010100051 in words is "one hundred five billion, ten million, one hundred thousand, fifty-one".

Divisors: 1 46933 2237447 105010100051