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105011343377 is a prime number
BaseRepresentation
bin110000111001100101…
…0011111000000010001
3101001001102100221222222
41201303022133000101
53210030400442002
6120124101310425
710405164456023
oct1416312370021
9331042327888
10105011343377
11405981905a6
1218428105415
139b96b10495
145122836013
152ae91821a2
hex187329f011

105011343377 has 2 divisors, whose sum is σ = 105011343378. Its totient is φ = 105011343376.

The previous prime is 105011343337. The next prime is 105011343419. The reversal of 105011343377 is 773343110501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104965632256 + 45711121 = 323984^2 + 6761^2 .

It is a cyclic number.

It is not a de Polignac number, because 105011343377 - 210 = 105011342353 is a prime.

It is a super-2 number, since 2×1050113433772 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105011343337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52505671688 + 52505671689.

It is an arithmetic number, because the mean of its divisors is an integer number (52505671689).

Almost surely, 2105011343377 is an apocalyptic number.

It is an amenable number.

105011343377 is a deficient number, since it is larger than the sum of its proper divisors (1).

105011343377 is an equidigital number, since it uses as much as digits as its factorization.

105011343377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26460, while the sum is 35.

Adding to 105011343377 its reverse (773343110501), we get a palindrome (878354453878).

The spelling of 105011343377 in words is "one hundred five billion, eleven million, three hundred forty-three thousand, three hundred seventy-seven".