Base | Representation |
---|---|
bin | 11110100100011001000… |
… | …11011000000010100001 |
3 | 10201102002022101121121211 |
4 | 33102030203120002201 |
5 | 114202034001311334 |
6 | 2122303123150121 |
7 | 135612105402016 |
oct | 17221443300241 |
9 | 3642068347554 |
10 | 1050330103969 |
11 | 375495a63a43 |
12 | 14b689515341 |
13 | 78079546753 |
14 | 38b9c94570d |
15 | 1c4c50b4a64 |
hex | f48c8d80a1 |
1050330103969 has 2 divisors, whose sum is σ = 1050330103970. Its totient is φ = 1050330103968.
The previous prime is 1050330103951. The next prime is 1050330103973. The reversal of 1050330103969 is 9693010330501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1033703290944 + 16626813025 = 1016712^2 + 128945^2 .
It is a cyclic number.
It is not a de Polignac number, because 1050330103969 - 215 = 1050330071201 is a prime.
It is a super-2 number, since 2×10503301039692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1050330103169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525165051984 + 525165051985.
It is an arithmetic number, because the mean of its divisors is an integer number (525165051985).
Almost surely, 21050330103969 is an apocalyptic number.
It is an amenable number.
1050330103969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1050330103969 is an equidigital number, since it uses as much as digits as its factorization.
1050330103969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 65610, while the sum is 40.
The spelling of 1050330103969 in words is "one trillion, fifty billion, three hundred thirty million, one hundred three thousand, nine hundred sixty-nine".
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