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105034347685153 is a prime number
BaseRepresentation
bin10111111000011100110110…
…111110111010010100100001
3111202220012000021122211220001
4113320130312332322110201
5102231340321001411103
61011220040241220001
731060324023333235
oct2770346676722441
9452805007584801
10105034347685153
11305158a9034997
12b94443a631601
13467b909249363
141bd19921c05c5
15c222b766d01d
hex5f8736fba521

105034347685153 has 2 divisors, whose sum is σ = 105034347685154. Its totient is φ = 105034347685152.

The previous prime is 105034347685123. The next prime is 105034347685177. The reversal of 105034347685153 is 351586743430501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82027292699664 + 23007054985489 = 9056892^2 + 4796567^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105034347685153 is a prime.

It is a super-2 number, since 2×1050343476851532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105034347685094 and 105034347685103.

It is not a weakly prime, because it can be changed into another prime (105034347685123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52517173842576 + 52517173842577.

It is an arithmetic number, because the mean of its divisors is an integer number (52517173842577).

Almost surely, 2105034347685153 is an apocalyptic number.

It is an amenable number.

105034347685153 is a deficient number, since it is larger than the sum of its proper divisors (1).

105034347685153 is an equidigital number, since it uses as much as digits as its factorization.

105034347685153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144000, while the sum is 55.

The spelling of 105034347685153 in words is "one hundred five trillion, thirty-four billion, three hundred forty-seven million, six hundred eighty-five thousand, one hundred fifty-three".