Base | Representation |
---|---|
bin | 11110100101111000100… |
… | …11111001001111101111 |
3 | 10201111011011002020100120 |
4 | 33102330103321033233 |
5 | 114210204111231142 |
6 | 2122514424500023 |
7 | 135641005034160 |
oct | 17227423711757 |
9 | 3644134066316 |
10 | 1051131352047 |
11 | 375867277537 |
12 | 14b87191a613 |
13 | 7817654573a |
14 | 38c37117767 |
15 | 1c5205d67ec |
hex | f4bc4f93ef |
1051131352047 has 16 divisors (see below), whose sum is σ = 1602091725312. Its totient is φ = 600508576800.
The previous prime is 1051131352043. The next prime is 1051131352099. The reversal of 1051131352047 is 7402531311501.
It is not a de Polignac number, because 1051131352047 - 22 = 1051131352043 is a prime.
It is a super-2 number, since 2×10511313520472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1051131351999 and 1051131352017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1051131352043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5652579 + ... + 5835572.
It is an arithmetic number, because the mean of its divisors is an integer number (100130732832).
Almost surely, 21051131352047 is an apocalyptic number.
1051131352047 is a deficient number, since it is larger than the sum of its proper divisors (550960373265).
1051131352047 is a wasteful number, since it uses less digits than its factorization.
1051131352047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11492518.
The product of its (nonzero) digits is 12600, while the sum is 33.
Adding to 1051131352047 its reverse (7402531311501), we get a palindrome (8453662663548).
The spelling of 1051131352047 in words is "one trillion, fifty-one billion, one hundred thirty-one million, three hundred fifty-two thousand, forty-seven".
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