Base | Representation |
---|---|
bin | 10011100101000011… |
… | …11100010101111011 |
3 | 1000010120010020020021 |
4 | 21302201330111323 |
5 | 133011411411011 |
6 | 4455012311311 |
7 | 521324503321 |
oct | 116241742573 |
9 | 30116106207 |
10 | 10511435131 |
11 | 450448187a |
12 | 2054312537 |
13 | cb6947402 |
14 | 71a053d11 |
15 | 417c34471 |
hex | 27287c57b |
10511435131 has 2 divisors, whose sum is σ = 10511435132. Its totient is φ = 10511435130.
The previous prime is 10511435089. The next prime is 10511435141. The reversal of 10511435131 is 13153411501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10511435131 - 211 = 10511433083 is a prime.
It is a super-2 number, since 2×105114351312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10511435096 and 10511435105.
It is not a weakly prime, because it can be changed into another prime (10511435141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5255717565 + 5255717566.
It is an arithmetic number, because the mean of its divisors is an integer number (5255717566).
Almost surely, 210511435131 is an apocalyptic number.
10511435131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10511435131 is an equidigital number, since it uses as much as digits as its factorization.
10511435131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 10511435131 its reverse (13153411501), we get a palindrome (23664846632).
The spelling of 10511435131 in words is "ten billion, five hundred eleven million, four hundred thirty-five thousand, one hundred thirty-one".
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