Base | Representation |
---|---|
bin | 10111111001101100111100… |
… | …110001001101011001010011 |
3 | 111210012101222112002111001202 |
4 | 113321230330301031121103 |
5 | 102234242431042234413 |
6 | 1011323341443021415 |
7 | 31066460056662143 |
oct | 2771547461153123 |
9 | 453171875074052 |
10 | 105120344102483 |
11 | 30549318845076 |
12 | b95903a66a86b |
13 | 4686a627942b8 |
14 | 1bd5bcd4b4923 |
15 | c2464c2b7e58 |
hex | 5f9b3cc4d653 |
105120344102483 has 2 divisors, whose sum is σ = 105120344102484. Its totient is φ = 105120344102482.
The previous prime is 105120344102453. The next prime is 105120344102567. The reversal of 105120344102483 is 384201443021501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 105120344102483 - 230 = 105119270360659 is a prime.
It is a super-2 number, since 2×1051203441024832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105120344102443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52560172051241 + 52560172051242.
It is an arithmetic number, because the mean of its divisors is an integer number (52560172051242).
Almost surely, 2105120344102483 is an apocalyptic number.
105120344102483 is a deficient number, since it is larger than the sum of its proper divisors (1).
105120344102483 is an equidigital number, since it uses as much as digits as its factorization.
105120344102483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 92160, while the sum is 38.
Adding to 105120344102483 its reverse (384201443021501), we get a palindrome (489321787123984).
The spelling of 105120344102483 in words is "one hundred five trillion, one hundred twenty billion, three hundred forty-four million, one hundred two thousand, four hundred eighty-three".
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