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105122135113 = 594671767739
BaseRepresentation
bin110000111100111000…
…1000111110001001001
3101001100010211202200121
41201321301013301021
53210242231310423
6120143100103241
710411011256012
oct1417161076111
9331303752617
10105122135113
1140644783016
1218459234b21
139bb3a62018
145133436009
152b03c6945d
hex1879c47c49

105122135113 has 4 divisors (see below), whose sum is σ = 105123962320. Its totient is φ = 105120307908.

The previous prime is 105122135071. The next prime is 105122135147. The reversal of 105122135113 is 311531221501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105122135113 is a prime.

It is a super-2 number, since 2×1051221351132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105122175113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 824403 + ... + 943336.

It is an arithmetic number, because the mean of its divisors is an integer number (26280990580).

Almost surely, 2105122135113 is an apocalyptic number.

It is an amenable number.

105122135113 is a deficient number, since it is larger than the sum of its proper divisors (1827207).

105122135113 is an equidigital number, since it uses as much as digits as its factorization.

105122135113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1827206.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 105122135113 its reverse (311531221501), we get a palindrome (416653356614).

The spelling of 105122135113 in words is "one hundred five billion, one hundred twenty-two million, one hundred thirty-five thousand, one hundred thirteen".

Divisors: 1 59467 1767739 105122135113