Base | Representation |
---|---|
bin | 11110100110001110000… |
… | …01110001010111011001 |
3 | 10201111121200101221112111 |
4 | 33103013001301113121 |
5 | 114211041123304203 |
6 | 2122544330312321 |
7 | 135645320223106 |
oct | 17230701612731 |
9 | 3644550357474 |
10 | 1051311150553 |
11 | 375949811844 |
12 | 14b901b886a1 |
13 | 781a48789a1 |
14 | 38c52d5baad |
15 | 1c5312a026d |
hex | f4c70715d9 |
1051311150553 has 2 divisors, whose sum is σ = 1051311150554. Its totient is φ = 1051311150552.
The previous prime is 1051311150521. The next prime is 1051311150559. The reversal of 1051311150553 is 3550511131501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 644251838409 + 407059312144 = 802653^2 + 638012^2 .
It is a cyclic number.
It is not a de Polignac number, because 1051311150553 - 25 = 1051311150521 is a prime.
It is a super-2 number, since 2×10513111505532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1051311150559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525655575276 + 525655575277.
It is an arithmetic number, because the mean of its divisors is an integer number (525655575277).
Almost surely, 21051311150553 is an apocalyptic number.
It is an amenable number.
1051311150553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1051311150553 is an equidigital number, since it uses as much as digits as its factorization.
1051311150553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5625, while the sum is 31.
The spelling of 1051311150553 in words is "one trillion, fifty-one billion, three hundred eleven million, one hundred fifty thousand, five hundred fifty-three".
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