Base | Representation |
---|---|
bin | 10011100101010001… |
… | …11000101011011011 |
3 | 1000010200112200210200 |
4 | 21302220320223123 |
5 | 133012343131011 |
6 | 4455115313243 |
7 | 521346123411 |
oct | 116250705333 |
9 | 30120480720 |
10 | 10513255131 |
11 | 4505505205 |
12 | 2054a4b823 |
13 | cb7133932 |
14 | 71a3a92b1 |
15 | 417e93856 |
hex | 272a38adb |
10513255131 has 24 divisors (see below), whose sum is σ = 15822534000. Its totient is φ = 6718444992.
The previous prime is 10513255097. The next prime is 10513255171. The reversal of 10513255131 is 13155231501.
10513255131 is a `hidden beast` number, since 1 + 0 + 51 + 32 + 551 + 31 = 666.
It is not a de Polignac number, because 10513255131 - 217 = 10513124059 is a prime.
It is a super-2 number, since 2×105132551312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10513255095 and 10513255104.
It is not an unprimeable number, because it can be changed into a prime (10513255171) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 108616 + ... + 181173.
It is an arithmetic number, because the mean of its divisors is an integer number (659272250).
Almost surely, 210513255131 is an apocalyptic number.
10513255131 is a deficient number, since it is larger than the sum of its proper divisors (5309278869).
10513255131 is a wasteful number, since it uses less digits than its factorization.
10513255131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289963 (or 289960 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 10513255131 its reverse (13155231501), we get a palindrome (23668486632).
The spelling of 10513255131 in words is "ten billion, five hundred thirteen million, two hundred fifty-five thousand, one hundred thirty-one".
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