Base | Representation |
---|---|
bin | 11110100110001111110… |
… | …10100101110100110011 |
3 | 10201111122201102200112212 |
4 | 33103013322211310303 |
5 | 114211103431423431 |
6 | 2122550021442335 |
7 | 135645560640431 |
oct | 17230772456463 |
9 | 3644581380485 |
10 | 1051326045491 |
11 | 375957165607 |
12 | 14b906b703ab |
13 | 781a7992567 |
14 | 38c54d17d51 |
15 | 1c53274372b |
hex | f4c7ea5d33 |
1051326045491 has 2 divisors, whose sum is σ = 1051326045492. Its totient is φ = 1051326045490.
The previous prime is 1051326045487. The next prime is 1051326045529. The reversal of 1051326045491 is 1945406231501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1051326045491 - 22 = 1051326045487 is a prime.
It is a super-2 number, since 2×10513260454912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1051326042491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525663022745 + 525663022746.
It is an arithmetic number, because the mean of its divisors is an integer number (525663022746).
Almost surely, 21051326045491 is an apocalyptic number.
1051326045491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1051326045491 is an equidigital number, since it uses as much as digits as its factorization.
1051326045491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 1051326045491 in words is "one trillion, fifty-one billion, three hundred twenty-six million, forty-five thousand, four hundred ninety-one".
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