Base | Representation |
---|---|
bin | 10011100101011100… |
… | …00011111110010001 |
3 | 1000010210002122020021 |
4 | 21302232003332101 |
5 | 133013220041423 |
6 | 4455204343441 |
7 | 521363504545 |
oct | 116256037621 |
9 | 30123078207 |
10 | 10514612113 |
11 | 4506251785 |
12 | 20553a4b81 |
13 | cb74ba495 |
14 | 71a63da25 |
15 | 41816095d |
hex | 272b83f91 |
10514612113 has 2 divisors, whose sum is σ = 10514612114. Its totient is φ = 10514612112.
The previous prime is 10514612077. The next prime is 10514612117. The reversal of 10514612113 is 31121641501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8756654929 + 1757957184 = 93577^2 + 41928^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10514612113 is a prime.
It is a super-2 number, since 2×105146121132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10514612117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5257306056 + 5257306057.
It is an arithmetic number, because the mean of its divisors is an integer number (5257306057).
Almost surely, 210514612113 is an apocalyptic number.
It is an amenable number.
10514612113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10514612113 is an equidigital number, since it uses as much as digits as its factorization.
10514612113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
It can be divided in two parts, 1051 and 4612113, that added together give a palindrome (4613164).
The spelling of 10514612113 in words is "ten billion, five hundred fourteen million, six hundred twelve thousand, one hundred thirteen".
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