Base | Representation |
---|---|
bin | 110000111111001101… |
… | …1011110011111001011 |
3 | 101001112121000100100020 |
4 | 1201332123132133023 |
5 | 3210422242101313 |
6 | 120154532311523 |
7 | 10412651124156 |
oct | 1417633363713 |
9 | 331477010306 |
10 | 105200347083 |
11 | 40684942907 |
12 | 1847b4725a3 |
13 | 9bc70175b0 |
14 | 513d994c9d |
15 | 2b0aa68323 |
hex | 187e6de7cb |
105200347083 has 32 divisors (see below), whose sum is σ = 151853087232. Its totient is φ = 64398067200.
The previous prime is 105200347061. The next prime is 105200347093. The reversal of 105200347083 is 380743002501.
It is not a de Polignac number, because 105200347083 - 224 = 105183569867 is a prime.
It is a super-2 number, since 2×1052003470832 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (105200347093) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9120666 + ... + 9132192.
It is an arithmetic number, because the mean of its divisors is an integer number (4745408976).
Almost surely, 2105200347083 is an apocalyptic number.
105200347083 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
105200347083 is a deficient number, since it is larger than the sum of its proper divisors (46652740149).
105200347083 is a wasteful number, since it uses less digits than its factorization.
105200347083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12755.
The product of its (nonzero) digits is 20160, while the sum is 33.
Adding to 105200347083 its reverse (380743002501), we get a palindrome (485943349584).
The spelling of 105200347083 in words is "one hundred five billion, two hundred million, three hundred forty-seven thousand, eighty-three".
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