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105212113 = 325132363
BaseRepresentation
bin1100100010101…
…10100011010001
321022222022212221
412101112203101
5203413241423
614235021041
72415200566
oct621264321
9238868787
10105212113
1154431466
122b29a781
1318a49cb6
14dd8a86d
159383e5d
hex64568d1

105212113 has 4 divisors (see below), whose sum is σ = 105247728. Its totient is φ = 105176500.

The previous prime is 105212111. The next prime is 105212123. The reversal of 105212113 is 311212501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 105212113 - 21 = 105212111 is a prime.

It is a super-2 number, since 2×1052121132 = 22139177443849538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105212111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12931 + ... + 19432.

It is an arithmetic number, because the mean of its divisors is an integer number (26311932).

Almost surely, 2105212113 is an apocalyptic number.

It is an amenable number.

105212113 is a deficient number, since it is larger than the sum of its proper divisors (35615).

105212113 is an equidigital number, since it uses as much as digits as its factorization.

105212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35614.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 105212113 is about 10257.2955987434. The cubic root of 105212113 is about 472.0868618866.

Adding to 105212113 its reverse (311212501), we get a palindrome (416424614).

The spelling of 105212113 in words is "one hundred five million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3251 32363 105212113