Base | Representation |
---|---|
bin | 11110101001011110101… |
… | …01111011010111110011 |
3 | 10201200010122112222001202 |
4 | 33110233111323113303 |
5 | 114223132140434013 |
6 | 2123434125321415 |
7 | 136036561030205 |
oct | 17245725732763 |
9 | 3650118488052 |
10 | 1053061264883 |
11 | 3766676a3621 |
12 | 15011010626b |
13 | 783c33206b4 |
14 | 38d7b56a775 |
15 | 1c5d4c52858 |
hex | f52f57b5f3 |
1053061264883 has 2 divisors, whose sum is σ = 1053061264884. Its totient is φ = 1053061264882.
The previous prime is 1053061264817. The next prime is 1053061264889. The reversal of 1053061264883 is 3884621603501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1053061264883 - 28 = 1053061264627 is a prime.
It is a super-3 number, since 3×10530612648833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1053061264889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526530632441 + 526530632442.
It is an arithmetic number, because the mean of its divisors is an integer number (526530632442).
Almost surely, 21053061264883 is an apocalyptic number.
1053061264883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053061264883 is an equidigital number, since it uses as much as digits as its factorization.
1053061264883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 829440, while the sum is 47.
The spelling of 1053061264883 in words is "one trillion, fifty-three billion, sixty-one million, two hundred sixty-four thousand, eight hundred eighty-three".
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