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1053136125193 is a prime number
BaseRepresentation
bin11110101001100111100…
…11011111110100001001
310201200022212102021002211
433110303303133310021
5114223310322001233
62123445402025121
7136041460235635
oct17246363376411
93650285367084
101053136125193
113766a5984249
121501311a81a1
13784059a1539
1438d87495dc5
151c5db5dd5cd
hexf533cdfd09

1053136125193 has 2 divisors, whose sum is σ = 1053136125194. Its totient is φ = 1053136125192.

The previous prime is 1053136125187. The next prime is 1053136125257. The reversal of 1053136125193 is 3915216313501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 788309585424 + 264826539769 = 887868^2 + 514613^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1053136125193 is a prime.

It is a super-2 number, since 2×10531361251932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1053136125593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526568062596 + 526568062597.

It is an arithmetic number, because the mean of its divisors is an integer number (526568062597).

Almost surely, 21053136125193 is an apocalyptic number.

It is an amenable number.

1053136125193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053136125193 is an equidigital number, since it uses as much as digits as its factorization.

1053136125193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72900, while the sum is 40.

The spelling of 1053136125193 in words is "one trillion, fifty-three billion, one hundred thirty-six million, one hundred twenty-five thousand, one hundred ninety-three".