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1053143231321 is a prime number
BaseRepresentation
bin11110101001101000011…
…10100110101101011001
310201200100100210021212202
433110310032212231121
5114223314131400241
62123450214215545
7136041604523336
oct17246416465531
93650310707782
101053143231321
113766a9998185
121501336545b5
13784072bbb4c
1438d883c598d
151c5dc043d9b
hexf5343a6b59

1053143231321 has 2 divisors, whose sum is σ = 1053143231322. Its totient is φ = 1053143231320.

The previous prime is 1053143231291. The next prime is 1053143231353. The reversal of 1053143231321 is 1231323413501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1051012485721 + 2130745600 = 1025189^2 + 46160^2 .

It is a cyclic number.

It is not a de Polignac number, because 1053143231321 - 210 = 1053143230297 is a prime.

It is a super-2 number, since 2×10531432313212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1053143233321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526571615660 + 526571615661.

It is an arithmetic number, because the mean of its divisors is an integer number (526571615661).

Almost surely, 21053143231321 is an apocalyptic number.

It is an amenable number.

1053143231321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053143231321 is an equidigital number, since it uses as much as digits as its factorization.

1053143231321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1053143231321 its reverse (1231323413501), we get a palindrome (2284466644822).

The spelling of 1053143231321 in words is "one trillion, fifty-three billion, one hundred forty-three million, two hundred thirty-one thousand, three hundred twenty-one".