Base | Representation |
---|---|
bin | 110001000011011100… |
… | …1100101000100110001 |
3 | 101001220111102020021122 |
4 | 1202012321211010301 |
5 | 3211220132043423 |
6 | 120221010232025 |
7 | 10416325050206 |
oct | 1420671450461 |
9 | 331814366248 |
10 | 105342456113 |
11 | 40748085494 |
12 | 184bab85615 |
13 | 9c1a5b288b |
14 | 51547c7cad |
15 | 2b182898c8 |
hex | 1886e65131 |
105342456113 has 2 divisors, whose sum is σ = 105342456114. Its totient is φ = 105342456112.
The previous prime is 105342456103. The next prime is 105342456119. The reversal of 105342456113 is 311654243501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102805520689 + 2536935424 = 320633^2 + 50368^2 .
It is a cyclic number.
It is not a de Polignac number, because 105342456113 - 24 = 105342456097 is a prime.
It is a super-2 number, since 2×1053424561132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105342456119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52671228056 + 52671228057.
It is an arithmetic number, because the mean of its divisors is an integer number (52671228057).
Almost surely, 2105342456113 is an apocalyptic number.
It is an amenable number.
105342456113 is a deficient number, since it is larger than the sum of its proper divisors (1).
105342456113 is an equidigital number, since it uses as much as digits as its factorization.
105342456113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 105342456113 its reverse (311654243501), we get a palindrome (416996699614).
The spelling of 105342456113 in words is "one hundred five billion, three hundred forty-two million, four hundred fifty-six thousand, one hundred thirteen".
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