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105342610433 is a prime number
BaseRepresentation
bin110001000011011101…
…0001010110000000001
3101001220111201001222012
41202012322022300001
53211220202013213
6120221013422305
710416326262134
oct1420672126001
9331814631865
10105342610433
1140748180425
12184bb03a995
139c1a637ba8
14515482821b
152b182ba4a8
hex1886e8ac01

105342610433 has 2 divisors, whose sum is σ = 105342610434. Its totient is φ = 105342610432.

The previous prime is 105342610427. The next prime is 105342610453. The reversal of 105342610433 is 334016243501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100586025409 + 4756585024 = 317153^2 + 68968^2 .

It is a cyclic number.

It is not a de Polignac number, because 105342610433 - 218 = 105342348289 is a prime.

It is a super-2 number, since 2×1053426104332 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 105342610433.

It is not a weakly prime, because it can be changed into another prime (105342610453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52671305216 + 52671305217.

It is an arithmetic number, because the mean of its divisors is an integer number (52671305217).

Almost surely, 2105342610433 is an apocalyptic number.

It is an amenable number.

105342610433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105342610433 is an equidigital number, since it uses as much as digits as its factorization.

105342610433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 105342610433 its reverse (334016243501), we get a palindrome (439358853934).

The spelling of 105342610433 in words is "one hundred five billion, three hundred forty-two million, six hundred ten thousand, four hundred thirty-three".